Answer / jitendera kumar sinha

procedure for 3ree way handshake protocol

Host A sends a TCP SYNchronize packet to Host B with sequance number x and tpdu

Host B receives A's SYN.and reply with its own sequnave nuber that is y.

Host B sends a SYNchronize-ACKnowledgement

Host A receives B's SYN-ACK

to establish a conection a client execute a connect primitive specifying the ip address and the port to which it want to connect.

thus from overall discussion we can say that the to establish connetion via 3reeeway host execute unicast message.

please mark if i wrong or right.your feddback i important to me
thanks
jitendera kumar sinha



Host A sends ACKnowledge

Host B receives ACK. TCP connection is ESTABLISHED.

from this it is look like a unicast msg.is not it.3ree way hand shake usage tcp not udp.so answer should be unicast.

Answer / mr.shahin07

Mr. Jitendera, Ur concept is little bit wrong. Three way
handshake process is lyk dis -

we assume a client computer is contacting a server to send
it some information.

1. The client sends a packet with the SYN bit set and a
sequence number of N.
2. The server sends a packet with an ACK number of N+1,
the SYN bit set and a sequence number of X.
3. The client sends a packet with an ACK number of X+1
and the connection is established.
4. The client sends the data.

Watever i think, It wud be UNICAST communication.


U Cn check this video also...

http://www.youtube.com/watch?v=z40w3G8szK0

Answer / jitendera kumar sinha

thank you very much for correction in my consept in
handshake 3ree way.by the way what is the exect answer of
that question.our answer are based upon theorytical concepts
so it might be wrong or wright.i have asked some of my
senior about that they told me it is unicast but they are
also not confirmed so i want to know exect answer.becoz on
yours explanation it is looking that you are also not sure

by the way thank you very much

jitenera kumar sinha

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