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a clock which gains uniformly was observed to be 5min
slow at 12 noon on monday. it was noticed 10 min fast at
6pm . on the next day .when did the watch show the correct
time (* PLEASE GIVE THE EXPLANATION*)
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Answer / yashwant
10pm on monday as watch was slow by 5min and it gained
uniformly so in 30 hrs it gained 15 min(10+5) to gain 5 min
it will take 10 hrs.
| Is This Answer Correct ? | 40 Yes | 6 No |
Answer / roy
10 pm on monday.
From 5 min slow to 10 min fast, the clock gained 15 mins
This it did in 30 hrs (12 noon to 12 noon plus 6 hrs next
day). so to gain 1 min it took 2 hrs (30/15). So to make up
the late timin of 5 mins (and thus to show the correct
timing) it will take 5*2=10 hrs. 12 noon to 10 hrs is 10pm.
| Is This Answer Correct ? | 24 Yes | 4 No |
Answer / swetha
It is 5 minutes slow at 12 noon and is seen to be 10 minutes fast at 6 pm the next day.So the total minutes which the clock has gained is 15 minutes. The total number of hours to gain 15 minutes is 30 hours.So to gain 5 minutes ,we have to cross multiply
2×30/15=10 hours
Therefore add 10 hours to 12 noon .You get the answer as 10 pm on the same day.
| Is This Answer Correct ? | 10 Yes | 0 No |
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