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What is the BOOT P protocol used for, where might you find
it in windows network infrastructure?
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Answer / ramprasad
BootP (RFC951) provides
* a unique IP address to the requester (using port 67)
similar to the DHCP request on port 68 AND
* can provide (where supported) the ability to boot a
system without a hard drive (ie: a diskless client)
Apple OS X 10.* Server supports BootP (albeit) renamed as
NetBoot. The facility allows the Admin to maintain a
selected set of configurations as boot images and then
assign sets of client systems to share(or boot from) that
image. For example Accounting, Management, and Engineering
departments have elements in common, but which can be unique
from other departments. Performing upgrades and maintenance
on three images is far more productive that working on all
client systems individually.
Startup is obviously network intensive, and beyond 40-50
clients, the Admin needs to
carefully subnet the infrastructure, use gigabit switches,
and host the images local to the clients to avoid saturating
the network. This will expand the number of BootP servers
and multiply the number of images, but the productivity of 1
BootP server per 50 clients is undeniable :)
Sunmicro, Linux, and AIX RS/600 all support BootP.
Todate, Windows does not support booting "diskless clients".
| Is This Answer Correct ? | 16 Yes | 0 No |
Answer / s.senthil62
before dhcp we using bootp(bootstrap), bootp coundnot find
the new updation we need to restart the system, but in dhcp
we no need to restart we find the new updation using
ipconfig/release and renew command. in bootp we couldnt
install os over the network.
| Is This Answer Correct ? | 15 Yes | 3 No |
Answer / anil4342
Bootp Protocal Will Work On DHCP Client's Systems.
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / shahil
before dhcp we using bootp(bootstrap), bootp coundnot find
the new updation we need to restart the system, but in dhcp
we no need to restart we find the new updation using
ipconfig/release and renew command. in bootp we couldnt
install os over the network.
| Is This Answer Correct ? | 0 Yes | 0 No |
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