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To move a Safe, two cylindrical steel bars 7 inches in
diameter are used as rollers.
How far will the safe have moved forward when the rollers
have made one revolution?
- 3 Answers
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Answer / guest
The safe must have moved 22 inches forward.
If the rollers make one revolution, the safe will move the
distance equal to the circumference of the roller. Hence,
the distance covered by the safe is
= PI * Diameter (or 2 * PI * Radius)
= PI * 7
= 3.14159265 * 7
= 21.99115
= 22 inches approx.
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / thiruppathi
radius = diameter/2=7/2 inches
circumference = 2* PI*radius
=2*(22/7)*(7/2)
=22 inches
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / alphy
21 inches.
from the initial position half rotation means it moves 14
inches 7+7 , full rotation means +7 14+7 = 21 inches.
| Is This Answer Correct ? | 0 Yes | 4 No |
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