Answer / vignesh1988i

super problem this is......

#include<stdio.h>
#include<conio.h>
void main()
{
int count ,m,n;
printf("enter the size :");
scanf("%d",&m);
printf("enter the seed :");
scanf("%d",&n);
count =n;
for(int i=1;i<=m;i++)
{
printf("\n");
for(j=1;j<=i;j++)
{
printf("%d",count);
count++;
if(count>=10)
count=1;
}
}
getch();
}

thank you

Answer / vignesh1988i

a smalll change in this program...... sorry for the inconvience

#include<stdio.h>
#include<conio.h>
void main()
{
int m,n;
printf("enter the size :");
scanf("%d",&m);
printf("enter the seed :");
scanf("%d",&n);
if(n>=10)
n=1;
for(int i=1;i<=m;i++)
{
printf("\n");
for(j=1;j<=i;j++)
{
printf("%d",n);
n++;
if(n>=10)
n=1;
}
}
getch();
}

Answer / prashant

#include<stdio.h>
#include<conio.h>
void main()
{
int i;
printf("enter the size");
scanf("%d",&n1);
printf("enter the seed");
scanf("%d",&n2);
for(i=1;i<n1;i++)
{
for(j=1;j<=i;j++)
{
printf("%d",j);
}
printf("\n");
}
getch();
}

Answer / dally

/////********For first question**********/
#include<stdio.h>
int main()
{
int n,i,j,k=1;

printf("Enter values for n\n") ;
scanf("%d",&n);
for(i=0;i<=n;i++)
{
for(j=0;j<=i;j++)
printf("%d\n",k);
printf("\n");
k++;
}
}
IT WILL PRINT
1
2 3
4 5 6
7 8 9 10

********************************
For second question
********************************

#include<stdio.h>
int main()
{
int i,j,n,k=3;

printf("Enter value for n\n") ;
scanf("%d",&n);

for(i=0;i<=n;i++)
{
for(j=0;j<=i;j++){
printf("%d",k);
k++;
}
printf("\n");
if(k == 10)
k=1;
}

}
IT WILL PRINT
3
45
678
9123
45678

A B C D E F G F E D C B A A B C D E F F E D C B A A B C D E E D C B A A B C D D C B A A B C C B A A B B A A A

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