main() { float a=3.2e40; printf("%d",a); }

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main()
{
float a=3.2e40;
printf("%d",a);
}

Question Posted / iftekhar

9 Answers
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main() { float a=3.2e40; printf("%d",a); }..

Answer / pankaj bhalerao

i run this and i found that the answer is zero because a
is declared as float and it is print ans integer and its
mantissa part is also a float therefore the output is zero.

thank you...

Is This Answer Correct ?

12 Yes

2 No

main() { float a=3.2e40; printf("%d",a); }..

Answer / pushpanjali panda

after running the program i got the answer is 0.

Is This Answer Correct ?

8 Yes

0 No

main() { float a=3.2e40; printf("%d",a); }..

Answer / iftekhar

main()
{
int i=300*300/300;
printf("%d",i);
}

Is This Answer Correct ?

12 Yes

9 No

main() { float a=3.2e40; printf("%d",a); }..

Answer / vignesh1988i

as for as i know ,
here however 'a' is a float variable when it comes
to printf , the floating numbers will be truncated and it
outputs as 3

thank u

Is This Answer Correct ?

11 Yes

9 No

main() { float a=3.2e40; printf("%d",a); }..

Answer / shashikanth

Is This Answer Correct ?

1 Yes

1 No

main() { float a=3.2e40; printf("%d",a); }..

Answer / rajendra chouhan

Is This Answer Correct ?

0 Yes

0 No

main() { float a=3.2e40; printf("%d",a); }..

Answer / deepali chandra

the o/p=0
because here we are trying to print the value in int form
which has been of float datatype.since float has a higher
precendence over int therefore it will give the o/p=0 and
similarly after this every output will be =0.this is the
function of the compiler that we cannot print the value of
a higher data type using a lower datatype.

Is This Answer Correct ?

0 Yes

1 No

main() { float a=3.2e40; printf("%d",a); }..

Answer / siva

a is declared as float but it is printed as integer so it
must be wrong.........

Is This Answer Correct ?

0 Yes

1 No

main() { float a=3.2e40; printf("%d",a); }..

Answer / vinaykumar

it is not execute, bcz in the printf satement declared as
integer so answer is 0.

Is This Answer Correct ?

0 Yes

1 No

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