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main()
{int a=200*200/100;
printf("%d",a);
}
- 14 Answers
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Answer / vishi
200*200=40000;
as the range of int(-32768 to +32767)
40000 exeeds +32767 &hence goes to the other side,
40000-32767=7233;
now (-32768+7233)=(-25535);
hence the value of 40000 will be -25535;
result be (-25535/100)="-255"(integer value).
| Is This Answer Correct ? | 25 Yes | 2 No |
Answer / pravin
200*200=40000;
as the range of int(-32768 to +32767)
40000 exeeds +32767 &hence goes to the other side,
40000-32767=7233;
now (-32768+7233)=(-25535);
hence the value of 40000 will be -25535;
result be (-24435/100)="-244"(integer value).
thank u
| Is This Answer Correct ? | 26 Yes | 10 No |
Answer / deepak roniya
explanation 7 is right......i also run this program and the
result is -255
| Is This Answer Correct ? | 11 Yes | 1 No |
Answer / vivek shah
because
int range 32767 to -32768
200*200=4000;
so out of range
-255
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / shafi
int a=200*200/100;/*it is related with assignment operator so
it's right->left shift*/
=200*2;
=400;
the value of a=400
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / tanvi jain
200*200=40000;
as the range of int(-32768 to +32767)
40000 exeeds +32767 &hence goes to the other side,
40000-32767=7233;
now (-32768+7233)=(-25535);
hence the value of 40000 will be -25535;
result be (-25535/100)="-255"(integer value).
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / xxxxxxx
among '* ','/' arithematic operators / has a higher
precedence.so 200/100 is enclosed in brackets and multiplied
with 200
so a=200*(200/100)=200*2=400
| Is This Answer Correct ? | 0 Yes | 1 No |
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