Out of 10 white, 9 black and 7 red balls, in how many ways
can we select one or more balls
please with solution.
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Answer / swethu
options are :a)234 b)52 c)630 d)879
but the suggested ans...is 879
| Is This Answer Correct ? | 24 Yes | 1 No |
Answer / sanjeev kumar
out of p alike things,q alikes things and r alike things, no of ways of selecting one or more = (p+1)*(q+1)*(r+1)-1.
so, (11*10*8)-1 =879
| Is This Answer Correct ? | 20 Yes | 1 No |
Answer / vanya
The previous answer(s) overlook the possibility that 0 balls can be selected from any color (i.e. 11,10, and 8 choices respectively), as long as all three numbers aren't zero. So it's:
(10+1)*(9+1)*(7+1) - 1 = 879
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / rohit
they are similar, hence answer would be different from the
above suggested
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / sudheer
we need to have one or more balls, so its like a position
where we should not be with no balls.
so answer is (total number of ways we can select the balls
in all possible ways) - (no. of ways where we don't have
any balls selected)
So, no. of ways where we don't have any balls selected =
10C0*9C0*7C0 = 1
total number of ways we can select the balls in all
possible ways = 10!*9!*7!/(10*9*7)
so, answer is ((10!*9!*7!)/(10*9*7)) - 1 =
| Is This Answer Correct ? | 9 Yes | 24 No |
pls send me the written test pattern of GE
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