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How to get EVEN & ODD numbers separately?
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Answer / amedela chandra sekhar
By using the condition in router transformation
drop the required ports into router t/r
add one group
even mod(empno,2)=0 ------Target1
defaultgroup -------------Target2
| Is This Answer Correct ? | 8 Yes | 1 No |
Answer / raghava
data one;
input number 10.;
datalines;
10
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;
run;
data two;
set one;
if mod(number,2)=0 Then A=number; else B=number;
/* number=mod(number);*/
run;
| Is This Answer Correct ? | 7 Yes | 0 No |
Answer / tejeya
By using the Sequence generator and Mod() in Expression tfn.
| Is This Answer Correct ? | 9 Yes | 6 No |
There are many ways....
1) Using the sql override in the source qualifier. To find
the even and odd. Add another column to flag the even and
odd.Like
select ID,decode( id/2,0,'E','O') FLAG FROM TABLE_NAME;
Using the router we can send them into two seperate target
tables.
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / amedela chandra sekhar
for above answer
Remember empno should be like
1
2
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9
other wise drag nextval port from sequence generator to
union t/r give condition like mod(nextval,2)0
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / prasad
no
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i wrote a condition in transformer if mod(no,2)=0 Then B else A
Target
A
1
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9
Target
B
2
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10
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / vali
by using the condition in expression transformation
mod(empno) .the output given torouter t/r. if the o.p is
zero given to one group and if one given to default group..
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / usha
by using Sequence Generator transformation we can get even
to one target and odd to other target
end valu=2
cycle should enable
start val=1
curr value=1
s-->sq-->seq-->RTR-->t1-->t2
| Is This Answer Correct ? | 1 Yes | 2 No |
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