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what is array?
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Answer / geetha gajendiran
array is a collection of similar data types;
i can explain with following example:
#include<stdio.h>
void main()
{
int x;
x=5;
x=10;
printf("\nx=%d",x);
}
here 10 is assigned to x.thereby 5 get lost.this is
applicable when only one value is stored.
but,if we want to store more than one value at a time in a
single variable.we go for using the array
suppose we want to arrange the payment of 100 workers in
ascending order.we have 2 options
1)construct 100 vari8ables to store the payment amount
obtained by 100 different workers.
2)construct one(1) variable (called array or subscripted
variable) capable of storing or holding all the hundred
values.
for more question and answers regarding computer
engineering please mail to me.
| Is This Answer Correct ? | 20 Yes | 4 No |
Answer / manishsharama
array is the collection of similar data type.
| Is This Answer Correct ? | 17 Yes | 6 No |
Answer / dharmendra jadeja
Array is a Collection of Elements of same datatypes.
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / niranjan
array is collection of similar types data which always
starts from o
| Is This Answer Correct ? | 9 Yes | 5 No |
Answer / nitesh pawar
Array means in short Array is group of variable which
having same name same data types but having differnt values
| Is This Answer Correct ? | 6 Yes | 2 No |
Answer / amit chauhan
Array is a collection of smiler data type.
address location of array starts from 0. OR
"It is a set of elements which stored under a single name". n
OR
"An array is a collection of homogenous data elements which
are stored in consecutive memory locations.
| Is This Answer Correct ? | 6 Yes | 3 No |
Answer / nikita
array is continous memory allocation for some data types.
<data ytpe> array name .[no of element].
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / gopi
An Array is a group of elements in a different datatype
| Is This Answer Correct ? | 11 Yes | 9 No |
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void main() { int s[4][2]={ {1234,56},{1212,33},{1434,80},{1312,78} }; int (*p)[2]; int i,j,*pint; for(i=0;i<=3;i++) { p=&s[i]; pint=p; printf("\n"); for(j=0;j<=1;j++) printf("%d",*(pint+j)); } } while running this program it shows a warning-suspicious pointer conversion ie pint=p; my que is why should we assign the value of p to pint again.why cant we use it directly as *(p+j)..but if i use like tat the o/p is garbage value..
C 
