Answer / ankit,rohit

#include<stdio.h>
#include<conio.h>
void main()
{
int sum=0,n,m,i;
clrscr();
scanf("%d",&i);
n=i;
m=n;
while(n>0)
{
m=n%10;
sum=sum+(m*m*m);
n=n/10;
}
if(i==sum)
{
printf("the given number is amstrong");
else
printf("the given number is not amstrong");
}
getch();
}

Given an array of size N in which every number is between 1 and N, determine if there are any duplicates in it. You are allowed to destroy the array if you like. [ I ended up giving about 4 or 5 different solutions for this, each supposedly better than the others ].

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