how to write a program to accept names and marks of 10
students from the user and display the names and markes of
only the passed students. Marks greater than or equal to
35 is considered as pass.
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Answer / vignesh1988i
#include<stdio.h>
void main()
{
char names[10][20];
int a[10][2],n;
printf(":enter the number of students :");
scanf("%d",&n);
printf("enter the names and marks");
for(int i=0;i<n;i++)
{
scanf("%s",names[i]);
scanf('%d",&a[i]);
}
printf("the passed students are :\n");
for(int i=0;i<n;i++)
{
if(a[i]>=35)
{
printf("%s",names[i]);
}
}
getch();
}
| Is This Answer Correct ? | 6 Yes | 3 No |
Answer / abikrishna
// Student Processing
#include <iostream>
using namespace std;
class Stud
{
public:
char name[20];
int marks[6];
};
int main ()
{
Stud s[11];int i,j,flag;
cout<<"\nEnter Name ";
for(i=0;i<10;i++)
cin>>s[i].name;
cout<<"\n Enter 5 marks ";
for(i=0;i<10;i++)
for(j=0;j<5;j++)
cin>>s[i].marks[j];
for(i=0;i<10;i++)
{flag=0;
for(j=0;j<5;j++)
if(s[i].marks[j]>=35)
flag++;
if(flag==5)
cout<<"\t"<<s[i].name;
}
return 0;
}
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / rakesh ramesh
'Code using dictionary object, Inputs are not restricted to
proper values
Function marks()
Dim dict , passed, name, studMark
Set dict = CreateObject("Scripting.Dictionary")
Set passed = createObject("Scripting.Dictionary")
for i=0 to 10
name = InputBox("Stud name :")
studmark= InputBox("enter mark :")
dict.Add name, mark
if studMark>34 then
passed.Add name, studmark
end if
Next
For each i in passed
msgbox i & " : " & passed(i) & " - is passed"
Next
End Function
Call marks()
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / sandeep chitta
set x=createobject("scripting.dictionary")
for i=1 to 10
x.add i,i*10
next
c=""
for i=1 to x.count
if x(i) >35 then
c=c&i&" "&x(i)&vbnewline
end if
next
msgbox c
| Is This Answer Correct ? | 0 Yes | 1 No |
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how to write a program to accept names and marks of 10 students from the user and display the names and markes of only the passed students. Marks greater than or equal to 35 is considered as pass.
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