Answer / virendra kumar

series of prime no

Answer / tuhin pal chowdhury

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int num;
int flag = 0;
cout<<"Enter a number"<<endl;
cin>>num;
for(int i=2;i<num;i++)
{
if((num%i) == 0)
{
flag = 1;
break;
}
}
if (flag == 1)
cout<<"Not Prime"<<endl;
else
cout<<"Prime"<<endl;
getch();
}

Answer / ashwin kanjariya

I accept the last function since it has less time complexity than all other functions........

Answer / garima gupta

#include<iostream.h>
#include<conio.h>
#include<math.h>
class prime
{
private:
int i,j,j;
public:
void readn();
void display();
};
void prime::readn()
{
clrscr();
cout<<"enter no. of prime nos you want to display:"<<endl;
cin>>n;
}
void prime::display()
{
int flag;
for(i=2;i<n;i++)
{
flag=0;
for(j=2;j<=sqrt(i);j++)
{
if(i%j==0)
{
flag=1;break;
}
else(flag==0)
{
cout<<i<<" ";
}
}
}
}
void main()
{
prime p;
p.readn();
p.display();
getch();
}

Answer / adnan sheikh

#include<iostream.h>
#include<conio.h>

main()
{
int i,j,num;
cout<<"enter nay number";
cin>>num;
j=static_cast<int>(num/2);
for(int i=2;i<=j;i++)
{
if(!(num%i))
break;
}
if(i==(j+1))
cout<<"number is prime";
else
cout<<"number is not prime";
getch();
}

Answer / pramod k sharma

#include<iostream.h>
#include<conio.h>
main()
{
int n,i,f=1;
cout<<"enter any no to check prime";
cin>>n;
for(i=2;i<n;i++)
{
if(n%i==0)
k=2;
}
if(k==2)
cout<<"the no is not prime"<<endl;
else
cout<<"the no is prime";
}
getch();

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