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quary for
1> fetch last record
2> fetch in reverse order
3> fetch last 5 row
4> fetch second last record (their is no primary key)
i think concept of count can be use for this in 4th
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Answer / sarath
1) select id,name from tab1 order by id desc fetch first
row only
2) select id,name from tab1 order by id desc
3) select id,name from tab1 order by id desc fetch first 5
rows only
4) select id,count(*),name from tab1 order by id where count
(*) = (select count(*) from tab1)-1
| Is This Answer Correct ? | 6 Yes | 3 No |
Answer / pavan
please try this one and let me know....
select * from emp where :ws-rec-cnt = (select Count(*)
into :ws-rec-cnt from emp);
| Is This Answer Correct ? | 3 Yes | 2 No |
Answer / pavan
the above one is for fetching last record and i think u can
decraese (use < symbol) the count and use it for fetching
nth record in a table.
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / sudipta
the 4th answer is(ignore the previous one)
db2=> with t1(a,b,c) as (select id,name,row_number()
over(order by id desc) as aa from tab1) select * from t1
where c=2
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / sudipta
u may try this
assuming table 'tab1' has 2 fields id & name
1) select id,name from tab1 order by id desc fetch first
row only
2) select id,name from tab1 order by id desc
3) select id,name from tab1 order by id desc fetch first 5
rows only
4) select id,count(*),name from tab1 order by id where count
(*)<(select count(*) from tab1)
u try these & if any problem u may write
| Is This Answer Correct ? | 0 Yes | 2 No |
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