please can anyone answer this query
Table 1 has 2 columns: EmployeeId,Age
Table 2 has 2 columns: EmployeeId, Region
Write SQL to Find the region who has the oldest person
Answers were Sorted based on User's Feedback
Answer / monal
SELECT REGION,AGE, T1.EMPID FROM T2 INNER JOIN T1
ON T1.EMPID = T2.EMPID WHERE AGE = (SELECT MAX(AGE) FROM T1)
Is This Answer Correct ? | 3 Yes | 0 No |
Answer / shivaraj
select region from table1 where employeeid in (select
employeeid from table2 where age in (select max(age) from
table2))
Is This Answer Correct ? | 3 Yes | 1 No |
Answer / krishna murari chaubey
create table Employee(empId int,age int)
create table Area(empId int,Region varchar(20))
Use Inner Join
select e.empid,e.age,a.region from Employee e inner join
area a on e.empid=a.empid and e.age in
(select max(age) from Employee)
OR
select empid,region from area where empid in
(select empid from Employee where age
in(select max(age) from Employee))
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / monal
SELECT REGION FROM T2 T2 INNER JOIN
T1 T1 ON T1.EMPID = T2.EMPID INNER JOIN
(SELECT MAX(AGE) AGE FROM T1) TBLAGE ON T1.AGE = TBLAGE.AGE
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / anil panwar
select t1.id, t2.region from table t1 left outer Join table2 t2
on t1.id=t2.id
where t1.id in (select id from table1 where age=(select
max(age) from table1))
Is This Answer Correct ? | 1 Yes | 1 No |
Answer / anil panwar
Hi Shivaraj
the ans you have given that is correct but
anyway,
if different employee id have same age and different region
and region is null in that case will not show Null region
for that employee
it may be solution....
select t1.id, t2.region from t1 left outer Join t2
on t1.id=t2.id
where t1.id in (select id from t1 where age=(select max(age)
from t1)) group by t1.id, t2.region
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / devendra sharma
select ID, region from tab1 where ID in
(select ID from tab2 where isnull(age,0)=(select max(age)
from tab2))
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / saravanan p
select e.empid,e2.region from empAge1 e,empAge2 e2
where e.empid=e2.empid and e.age in(select max(age) from
empAge1)
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / gayathri
create table Emp1(EmployeeId int, Age int);
INSERT into Emp1 Values(1,20);
INSERT into Emp1 Values(2,20);
INSERT into Emp1 Values(3,25);
INSERT into Emp1 Values(4,25);
INSERT into Emp1 Values(5,30);
INSERT into Emp1 Values(6,30);
INSERT into Emp1 Values(7,30);
create table Emp_details(EmployeeId int, Region cahr(10));
INSERT into Emp_details Values(1,'del');
INSERT into Emp_details Values(2,'chn');
INSERT into Emp_details Values(3,'mum');
INSERT into Emp_details Values(4,'del');
INSERT into Emp_details Values(5,'cal');
INSERT into Emp_details Values(6,'mum');
INSERT into Emp_details Values(7,'chn');
select Region from Emp_details ed,Emp1 e1
where e1.EmployeeId = ed.EmployeeId
and e1.Age = (select max(Age) from emp1);
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / ramesh babu
Create table #tempempid(Employeeid int,age int)
Create table #tempempregion(Employeeid int,Region varchar
(200))
Insert into #tempempid(Employeeid,age)values(100,25),
(101,35),(103,35),(104,10),(105,12),(106,11),(107,13),
(108,24),(109,22),(110,17),(111,11),(112,25),(113,100) ,
(52,100)
go
Insert into #tempempregion(Employeeid,region)values
(100,'SA'),(102,'SA'),(103,'UK'),(104,'UK'),(105,'PHL'),
(106,'US'),(107,'US'),(108,'US'),(109,'RSA'),(110,'RSA'),
(111,'UK'),(113,'SA'),(52,'CA')
Select T.region,T.Age from
(
Select b.region as Region,a.age as Age,
rank() over(order by age desc) as Rnk
from #tempempid a inner join #tempempregion b on
a.Employeeid=b.Employeeid
)T
Where T.Rnk=1
Is This Answer Correct ? | 0 Yes | 0 No |
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