main() { int i = 1; int num[] = {1,2,3,4}; num[i] = i++; printf(&qu

Categories >> Software >> Programming Languages >> C
Suggest New Category

main()
{
int i = 1;
int num[] = {1,2,3,4};
num[i] = i++;
printf("%d", num[i]);
}

what will be the output?
}

Question Posted / sid08

22 Answers
27744 Views
NDS, TCS, I also Faced
E-Mail Answers

Answers were Sorted based on User's Feedback

main() { int i = 1; int num[] = {1,2,3,4}; num[i] = i++; printf("%d", num[i])..

Answer / revathi

Correct Answer is 3.

Do not post wrong answer.

Is This Answer Correct ?

1 Yes

0 No

main() { int i = 1; int num[] = {1,2,3,4}; num[i] = i++; printf("%d", num[i])..

Answer / james holdcroft

The output will be 1 or 3, depending on the compiler.

Quoting from "The C Programming Language, Second Edition"
by Kernighan and Ritchie:

C, like most languages, does not specify the order in which
operands of an operator are evaluated. (The exceptions are
&&, ||, ?:, and ','.)
...
One unhappy situation is typified by the statement
a[i] = i++;
The question is whether the subscript is the old value of i
or the new. Compilers can interpret this in different
ways, and generate different answers depending on their
interpretation.

Is This Answer Correct ?

0 Yes

0 No

main() { int i = 1; int num[] = {1,2,3,4}; num[i] = i++; printf("%d", num[i])..

Answer / gowtham

complier error

Is This Answer Correct ?

13 Yes

14 No

main() { int i = 1; int num[] = {1,2,3,4}; num[i] = i++; printf("%d", num[i])..

Answer / aniruddha

It will print answer 1 because in case of++ atfairt assing
and then increment..

Is This Answer Correct ?

5 Yes

6 No

main() { int i = 1; int num[] = {1,2,3,4}; num[i] = i++; printf("%d", num[i])..

Answer / ismail

2 is the ans

num[i]=i++
num[1]=2

now num[1] is changed with 2(same as the previous value)
now to print num[i]=num[1] right?
its 2 which is in num[1] solved!!!!

Is This Answer Correct ?

0 Yes

1 No

main() { int i = 1; int num[] = {1,2,3,4}; num[i] = i++; printf("%d", num[i])..

Answer / vijay

main()
{
int i = 1;
int num[] = {1,2,3,4};
num[i] = i++; //num[2]=1; after compile time
printf("%d", num[i]);
}
}

output:- 1

//if you have R&D mode then send the your view .No doubt ,
//it is correct.

Is This Answer Correct ?

0 Yes

3 No

main() { int i = 1; int num[] = {1,2,3,4}; num[i] = i++; printf("%d", num[i])..

Answer / lukz

4 is output

Is This Answer Correct ?

2 Yes

7 No

main() { int i = 1; int num[] = {1,2,3,4}; num[i] = i++; printf("%d", num[i])..

Answer / abdur rab

it will lead to Undefined behaviour, both answers 3 aand 4
are correct.

Is This Answer Correct ?

0 Yes

5 No

main() { int i = 1; int num[] = {1,2,3,4}; num[i] = i++; printf("%d", num[i])..

Answer / ssssssssss

output
2

Is This Answer Correct ?

1 Yes

6 No

main() { int i = 1; int num[] = {1,2,3,4}; num[i] = i++; printf("%d", num[i])..

Answer / raju

correct answer is 2 bcz once assign only that will take as
that value

Is This Answer Correct ?

0 Yes

6 No

Post New Answer