Answer / abc

each bucket has 10 kb
so N kb wants N/10 buckets..
0.0001kb filled in 1ms
so 10 kb ll be filled in 10/0.0001ms=100000ms
sender to receiver s 10ms
ack is 100 ms
so total time for 1 bucket is (100000+10+100)ms=100110ms
for N/10 buckets it s 100110*N/10 ms=10011 ms=10.011s

Answer / abc

tat s 10.011N s

Answer / asdf

1.01*n s

n/10 buckets are needed ...

for each bucket 10 sec and ack takes 0.1 sec

Answer / umang

time taken for successfully transfer for N kb file
=[(N/10)*100]+[(0.11)*{(N mod 10)+1}]

Answer / purevial

Size of File = N kb
Time Taken to Fill a bucket = 0.0001kb/ms * 10kb = 0.001ms
Time To Send a bucket = 10ms
No. of buckets = N/10
After 0.001ms + 10ms, the sending side waits for ACK so as
to start with the next bucket
So Total Time = ( 0.001ms + 10ms + 100ms) per bucket.
Total time per N/10 buckets = (110.001)(N/10) ms
= 11.0001 N ms
or 0.0110001 N ms

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