Answer / ashu

divide the given no by two n store the remainder in stack
and divide again by 2 to quotent the process gong on....
n store all the remainder in the same stack....
n in last pop all the element from stack n print it.

Answer / siddiqui mohd. faisal

It's very simple.
Firstly, the binary no. of 0 is 0000.
After that if you want to know the binary no. of 1 then
jaust add 1 to binary no. of 0 i.e. 0000.So, now the ans
will be 0001.But,remember here 1+1=10.So, now if you want
binary no. of 2 then add 1 to binary no. of 1 i.e. 0001.So,
the binary no. of 2 will be 0010.
I hope you got your question answer.

Answer / vaibhav

divide no. by 2 till 1 is not coming in quotient, then it
write from bottom to top

Answer / santhi perumal

#include<stdio.h>
#include<conio.h>

int main()
{
int i,number;
printf("Enter the Number\n");
scanf("%d",&number);

for(i=7;i>=0;i--)
{
if((1<<i) & number)
printf("1");
else
printf("0");
}
}

Answer / alle balraj

void main()
{
int i,n,p=0,j;
int a[10];
clrscr();
printf("Enter the value of n:\n");
scanf("%d",&n);
i=n;
while(i!=1)
{
if(n==1)
{
a[p]=1;
break;
}
if(n%2==0)
{
a[p]=n%2;
}
else
{
a[p]=n%2;
}
n=n/2;
i=n+2;
i--;
p++;
}
for(j=p;j>=0;j--)
{
printf("%d",a[j]);
}

getch();
}

Answer / bertilla

#include<conio.h>
#include<stdio.h>
void main()
{
int i,n,arr[15];
for(i=0;i<=14;i++){arr[i]=0;}
do
{
arr[i]=n%2;
n=n/2;
i--;
if(n==1){arr[i]=1;}
}while(n>1);
for(i=0;i<=15;i++)
{
printf("%d",arr[i]);
}
getch();
}

Answer / naresh m

main()
{
int a[12],n,m,i=0;
printf("enter the no to find binary no's");
scanf("%d",&n);
while(n!=0)
{
m=i++;
a[i]=n%2;
n=n/2;
}
printf("binary value is");
for(i=m;i>=0;i--)
{
printf("%d",a[i]);
}

Answer / kk

let the number be n
int bin(int n)
{
static int sum=0;

if(n>1)
{
rem=n%2;
sum = sum *10 +rem;
n=n/2;
bin(n);
}
else
{
sum=sum*10+1;
}
return sum;
}

Answer / a.balraj

void main()
{
int i,n,p=0,temp,z;
int a[3];
clrscr();
printf("Enter the value of n:\n");
scanf("%d",&n);
i=n;
while(i!=1)
{
if(n%2==0)
{
temp=n%2;
}
else
{
temp=n%2;
}
a[p]=temp;
n=n/2;
i=n+2;
i--;
p++;
}
for(z=sizeof(a)/sizeof(int);z>=0;z--)
{
printf("%d",a[z]);
}
getch();
}

Answer / subhashini

#include<stdio.h>
#include<conio.h>
{
clrscr();
int i,sum,n;
printf("enter the number");
scanf("%d",&n);
while(n>=1)
{
i=n%2;
sum=sum*10+i;
n=n/2;
getch();
}
printf("the binary number is: %d",i)

1 1 1 1 2 1 1 3 3 1 1 4 6 4 1

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