main() { charstr1="prakash"; charstr2="raju"; Str1=str2;

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main()
{
charstr1="prakash";
charstr2="raju";
Str1=str2;
printf("\n%d",str1);
}

Question Posted / guest

7 Answers
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main() { charstr1="prakash"; charstr2="raju"; Str1=str2; printf("\n%d&..

Answer / kk

Error
An array of string cannot be directly assigned to other;
soln: char *str1="prakash"
char *str2="raju"
str1=str2;

Is This Answer Correct ?

17 Yes

2 No

main() { charstr1="prakash"; charstr2="raju"; Str1=str2; printf("\n%d&..

Answer / naman patidar

compile time error at line 3 and 4.
can not assign string to char ( i.e. to str1 and str2).

Is This Answer Correct ?

14 Yes

3 No

main() { charstr1="prakash"; charstr2="raju"; Str1=str2; printf("\n%d&..

Answer / app

Error
Since address of different strings are compared

Is This Answer Correct ?

2 Yes

0 No

main() { charstr1="prakash"; charstr2="raju"; Str1=str2; printf("\n%d&..

Answer / kas

well the program will run finely ... with some warnings
of course ...

This is what I got as "out put" of the program using Fedora13...

Warning: multi-character character constant
In function 'main'
Warning: overflow in implicit constant conversion ...

But the RESULT was given as the ASCII of the last character
of the second string ..
That is in this case the answer will be "117";
Hope it helps ... :D

Is This Answer Correct ?

1 Yes

0 No

main() { charstr1="prakash"; charstr2="raju"; Str1=str2; printf("\n%d&..

Answer / ashok kumar

error

Is This Answer Correct ?

0 Yes

0 No

main() { charstr1="prakash"; charstr2="raju"; Str1=str2; printf("\n%d&..

Answer / vignesh1988i

ascii value of 'r' will get printed