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logic for generating all the combinations of the any number
of given letters.
ex:::::::::
if a,b,c,d are given the o/p should be
abcd,dcba,dbac,bcad,................
4*3*2*1 combinations............
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Answer / abdur rab
#include <stdio.h>
void permute ( char* strptr, int start, int length )
{
int count1;
int count2;
int temp;
for ( count1 = start; count1 < length - 1;
++count1 ) {
for ( count2 = count1 + 1; count2 < length;
++count2 ) {
temp = strptr [ count1 ]; strptr [
count1 ] = strptr [ count2 ]; strptr [ count2 ] = temp;
permute ( strptr, count1 + 1,
length );
temp = strptr [ count1 ]; strptr [
count1 ] = strptr [ count2 ]; strptr [ count2 ] = temp;
}
}
printf ( "\n%s", strptr );
}
int main ( int argc, char* argv [] )
{
char str[] = "abcd";
permute ( str, 0, ( strlen ( str ) ) );
return 0;
}
| Is This Answer Correct ? | 7 Yes | 4 No |
Answer / ashok kannan
#include<stdio.h>
#include<conio.h>
#include<string.h>
char a[10];
int m;
void permute(int n,int i)
{
int j;
for(j=i;j<m;j++)
{
printf("%c",a[j]);
if(n!=0)
{
permute(n-1,i+1);
}
else
{
printf("%c\n",a[j]);
}
}
void main()
{
printf("enter the string to be permuted");
scanf("%s",a);
m=strlen(a);
permute(m,0);
}
| Is This Answer Correct ? | 2 Yes | 4 No |
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