Answer / zain

#include<iostream>
using namespace std;
int LCM(int a,int b);
int main()
{
int a,b;
cout<<" ENTER TWO NUMBER : ";
cin>>a>>b;
cout<<"\n\n LCM : "<<LCM(a,b);
system("pause");
return 0;
}
int LCM(int a,int b)
{
int n;
for(n=1;;n++)
{
if(n%a == 0 && n%b == 0)
return n;
}
}

Answer / sudhir

int gcd(int a, int b)
{
if (a==0 && b==0) return -1;
if (b==0) return a;
return gcd(b,a%b);
}


int lcm (int a, int b)
{
return (int) (a*b)/gcd(a,b);
}

Answer / mohit

#include <stdio.h>


main()
{
int a,b,n=2,res=1;
printf("Enter two integers : ");
scanf("%d %d",&a,&b);
while((a!=1)||(b!=1))
{
if((a%n==0)&&(b%n==0))
{
a/=n;
b/=n;
res*=n;
}

else if((a%n==0)&&(b%n!=0))
{
a/=n;
res*=n;

}

else if((a%n!=0)&&(b%n==0))
{
b/=n;
res*=n;

}

else if((a%n!=0)&&(b%n!=0))
{
n++;
}

}
printf("\n LCM of a and b is %d",res);

}

Answer / khadanga

public class LCM {

public static void main(String a[]){
test(0,9);
}

static void test(int a,int b){
if(a==0 || b==0){
return;
}
int n;
int increment;
if(a>b){
n = a;
increment = a;
}else{
n = b;
increment = b;
}

while(true){
if(n%a == 0 && n%b == 0){
break;
}else if(n > (a*b)){
n = a*b;
break;
}else{
n = n+increment;
}
}

System.out.println("LCM for "+a+" and "+b+" is "+n);
}

}

Answer / shailendra

#include <iostream>
using namespace std;
int main()
{
int x,y,z;
cout<<"Enter First Integer:";
cin>>x;
cout<<"\nEnter Second Integer:";
cin>>y;
z=1;
while(x/z==1 && y/z==1)
{
z=x/y;
cout<<"The LCM of Both Numbers is:"<<z;
}
return 0;
}

design a counter with the following repeated binary sequence: 0, 1, 2, 3, 4, 5, 6, 7, 8 using JK Flip Flop.

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hai i like to do some certifications in programming or any other......... am doing my IT third year......... pls guide me...... mail me ur suggestions to ranjithmaharaj@gmail.com...

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