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Write a Pseudo Code to fins the LCM of two given numbers
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Answer / zain
#include<iostream>
using namespace std;
int LCM(int a,int b);
int main()
{
int a,b;
cout<<" ENTER TWO NUMBER : ";
cin>>a>>b;
cout<<"\n\n LCM : "<<LCM(a,b);
system("pause");
return 0;
}
int LCM(int a,int b)
{
int n;
for(n=1;;n++)
{
if(n%a == 0 && n%b == 0)
return n;
}
}
| Is This Answer Correct ? | 49 Yes | 23 No |
Answer / sudhir
int gcd(int a, int b)
{
if (a==0 && b==0) return -1;
if (b==0) return a;
return gcd(b,a%b);
}
int lcm (int a, int b)
{
return (int) (a*b)/gcd(a,b);
}
| Is This Answer Correct ? | 22 Yes | 4 No |
Answer / mohit
#include <stdio.h>
main()
{
int a,b,n=2,res=1;
printf("Enter two integers : ");
scanf("%d %d",&a,&b);
while((a!=1)||(b!=1))
{
if((a%n==0)&&(b%n==0))
{
a/=n;
b/=n;
res*=n;
}
else if((a%n==0)&&(b%n!=0))
{
a/=n;
res*=n;
}
else if((a%n!=0)&&(b%n==0))
{
b/=n;
res*=n;
}
else if((a%n!=0)&&(b%n!=0))
{
n++;
}
}
printf("\n LCM of a and b is %d",res);
}
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / khadanga
public class LCM {
public static void main(String a[]){
test(0,9);
}
static void test(int a,int b){
if(a==0 || b==0){
return;
}
int n;
int increment;
if(a>b){
n = a;
increment = a;
}else{
n = b;
increment = b;
}
while(true){
if(n%a == 0 && n%b == 0){
break;
}else if(n > (a*b)){
n = a*b;
break;
}else{
n = n+increment;
}
}
System.out.println("LCM for "+a+" and "+b+" is "+n);
}
}
| Is This Answer Correct ? | 3 Yes | 6 No |
Answer / shailendra
#include <iostream>
using namespace std;
int main()
{
int x,y,z;
cout<<"Enter First Integer:";
cin>>x;
cout<<"\nEnter Second Integer:";
cin>>y;
z=1;
while(x/z==1 && y/z==1)
{
z=x/y;
cout<<"The LCM of Both Numbers is:"<<z;
}
return 0;
}
| Is This Answer Correct ? | 8 Yes | 69 No |
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