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What is the output generated by the following code?
01 GRP-I.
05 SUBFLD1 PIC XX VALUE "AB".
05 FILTER PIC X(6) VALUE SPACES.
01 GRP-2 REDEFINED GRP-1.
05 SUB-FLD2 PIC XX.
05 SUB-FLD3 PIC XX.
05 FILTER PIC X(4).
IF SUB-FLD1 NOT = SPACES
DISPLAY "SUBFLD1"
MOVE "ABBCCD" TO GRP-1
IF SUB-FLD3 = SPACES
DISPLAY "SPACES"
ELSE
DISPLAY "SUBFLD3"
DISPLAY "END"
ELSE
DISPLAY "SPACES"
DISPLAY "END".
(a) SUBFLD1
SUBFLD3
END
(b) SPACES
END
(c) SUBFLD1
END
(d) SUBFLD1
SPACES
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Answer / vish
I doubt if we can code like IF ELSE ELSE....since no scope
terminatior (END-IF) has been given for the nested IF ELSE
so it should throw a compilation error. It can display the
output as (a) ONLY if the code is something like below:
01 GRP-1.
05 SUBFLD1 PIC XX VALUE "AB".
05 FILTER PIC X(6) VALUE SPACES.
01 GRP-2 REDEFINED GRP-1.
05 SUB-FLD2 PIC XX.
05 SUB-FLD3 PIC XX.
05 FILTER PIC X(4).
IF SUB-FLD1 NOT = SPACES
DISPLAY "SUBFLD1"
MOVE "ABBCCD" TO GRP-1
IF SUB-FLD3 = SPACES
DISPLAY "SPACES"
ELSE
DISPLAY "SUBFLD3"
DISPLAY "END"
END-IF
ELSE
DISPLAY "SPACES"
DISPLAY "END".
Please correct me if I am wrong.
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / vish
Uttam, I guess you missed to see the REDEFINES part of the
code given. It's moving 'ABBCCD' to GRP-1 and since GRP-2
REDEFINES GRP-1, the variables in GRP-2 also will be
populated and then naturally SUB-FLD3 is not SPACES and
contain 'BC'. So the correct answer is (a).
I request - please don't be in hurry to answer the
questions. A lot many people build their concepts based on
the questions & queswers provided in such groups.
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / guest
I hope SUBFLD1 is erroneously written as SUB-FLD1
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / muttaiah
I guess we will get Maxcc - 8 when we compile. Because
SUB-FLD1 is not declared anywhere here. If the field has to
be SUBFLD1 by typo mistake.
Then answer would be (a).
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / uttam das
my answer is (d)
SUB-FLD3 = SPACES, it satisfies bcz in grp-2
there is no initialization of sub-fld3.
when sub-fld3 is not initialize, it always contains spaces.
alphanumeric stored spaces and numeric stored zeros
| Is This Answer Correct ? | 0 Yes | 5 No |
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