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how to find the size of the data type like int,float
without using the sizeof operator?
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Answer / abhishek pathak mnnit
#include <stdio.h>
#define sizeof(x) ((void *)(&x + 1) - (void *)(&x))
void main()
{
int a;
printf("int size=%d",sizeof(a));
}
| Is This Answer Correct ? | 3 Yes | 8 No |
Answer / vignesh1988i
#include<stdio.h>
#include<conio.h>
void main()
{
int ptr,a[2];
char ptr1,b[2];
float ptr2,c[2];
ptr=(a+1)-a;
ptr1=(b+1)-b;
ptr2=(c+1)-c;
printf("int : %d\n",ptr);
printf("char : %d\n",ptr1);
printf('float : %d\n",ptr2);
getch();
}
than ku
| Is This Answer Correct ? | 0 Yes | 8 No |
Answer / ravi.jnv
Its possible by pointers.
-----------------
int one,two;
int *ptrOfOne,*ptrOfTwo;
int size;
ptrOfOne = &one;
ptrOfTwo = &two;
size = ptrOfOne - ptrOfTwo ; /* u can get minus value also
depending upon stack how it pushes variables */
| Is This Answer Correct ? | 6 Yes | 28 No |
write a program for 4 4 3 3 3 3 2 2 2 2 2 2 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 2 2 2 2 2 2 3 3 3 3 4 4
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