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How to add two numbers without using arithmetic operators?
- 18 Answers
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Answer / ramanareddy
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c;
clrscr();
printf("enter the two numbers");
scanf("%d %d",%a,&b);
c=(-(-a-b));
printf("sum is = %d",c");
getch();
}
| Is This Answer Correct ? | 0 Yes | 4 No |
Answer / abhishek shukla
what will be output of this programme?
#include<stdio.h>
#include<conio.h>
void main()
{
int a=5;
clrscr();
a=a+(2,3,3,5,8,6);
printf("%d",a);
getch();
}
| Is This Answer Correct ? | 1 Yes | 6 No |
Answer / pugalarasu
int sum(int num1,int num2)
{
for(int i=0;i<num2;i++)
num1++;
return num1;
}
| Is This Answer Correct ? | 39 Yes | 50 No |
Answer / ranjith
#include<stdio.h>
main()
{
int a=5,b=4,c;
c=a||b;
printf("sum="+c);
}
| Is This Answer Correct ? | 2 Yes | 21 No |
Answer / suhas
# include <stdio.h>
main()
{
int a=8,b=2;
a|=b;
printf("sum="+a);
}
| Is This Answer Correct ? | 7 Yes | 43 No |
Answer / kavi
#include<stdio.h>
int a,b,c;
{
printf("enter the two values");
scanf("%d","%d",&a,&b);
c=a||b;
}
| Is This Answer Correct ? | 10 Yes | 80 No |
Answer / prashant
even this gives the same ans as the above program gives...
just every one plz check it and tell me
#include<stdio.h>
#include<math.h>
int main()
{
int a,b,c;
printf("enter the nos");
scanf("%d %d",&b,&c);
a= (b^c);
printf("%d",a);
return 0;
}
| Is This Answer Correct ? | 19 Yes | 114 No |
#include<stdio.h> #include<conio.h> void main() {clrscr(); char another='y'; int num; for(;another=='y';) { printf("Enter a number"); scanf("%d",&num); printf("squre of %d is %d",num,num*num); printf("\nwant to enter another number y/n"); scanf("%c",&another); } getch(); } the above code runs only one time.on entering 'y' the screen disappeares.what can i do?
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