I ASKED A WOMAN WHAT WAS HER AGE?. SHE REPLIED THAT HER
HUSBAND'S AGE IS REVERSE OF HER. AND THE DIFFERENCE BETWEEN
THEIR AGES IS ONE ELEVENTH OF THEIR SUM. FIND OUT WHAT WAS
HER AGE AND HER HUSBAND'S AGE?.
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Answer / ilakya.g
IT WAS 45 FOR THE WOMAN, AND IT WAS 54 FOR HER HUSBAND.
54-45=9.
54+45=99.
(1/11)99=9.
SO THE ANSWER IS 45 AND 54.
| Is This Answer Correct ? | 9 Yes | 0 No |
Answer / mansoor sarfraz
woman age = 10x + y
husband age = 10y + x
diff in ages = sum of ages/11
(10x + y) - (10y + x) = 1/11(10x + y + 10y + x)
9x - 9y = 1/11(11x + 11y)
9(x-y) = x+ y
9x - x = y + 9y
8x = 10y
x = 10y/8
put different values of y (y =1,2,3,4.........) to get
whole value of x
put y = 4, x = 5 satisfies the condition
woman age = 10(5) + 4
= 54
husband age = 45
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / take
IT WAS 45 FOR THE WOMAN, AND IT WAS 54 FOR HER HUSBAND.
54-45=9.
54+45=99.
(1/11)99=9.
SO THE ANSWER IS 45 AND 54.
woman age = 10x + y
husband age = 10y + x
diff in ages = sum of ages/11
(10x + y) - (10y + x) = 1/11(10x + y + 10y + x)
9x - 9y = 1/11(11x + 11y)
9(x-y) = x+ y
9x - x = y + 9y
8x = 10y
x = 10y/8
put different values of y (y =1,2,3,4.........) to get
whole value of x
put y = 4, x = 5 satisfies the condition
woman age = 10(5) + 4
= 54
husband age = 45
| Is This Answer Correct ? | 1 Yes | 0 No |
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