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I ASKED A WOMAN WHAT WAS HER AGE?. SHE REPLIED THAT HER
HUSBAND'S AGE IS REVERSE OF HER. AND THE DIFFERENCE BETWEEN
THEIR AGES IS ONE ELEVENTH OF THEIR SUM. FIND OUT WHAT WAS
HER AGE AND HER HUSBAND'S AGE?.

Answers were Sorted based on User's Feedback



I ASKED A WOMAN WHAT WAS HER AGE?. SHE REPLIED THAT HER HUSBAND'S AGE IS REVERSE OF HER. AND ..

Answer / ilakya.g

IT WAS 45 FOR THE WOMAN, AND IT WAS 54 FOR HER HUSBAND.
54-45=9.
54+45=99.
(1/11)99=9.

SO THE ANSWER IS 45 AND 54.

Is This Answer Correct ?    9 Yes 0 No

I ASKED A WOMAN WHAT WAS HER AGE?. SHE REPLIED THAT HER HUSBAND'S AGE IS REVERSE OF HER. AND ..

Answer / mansoor sarfraz

woman age = 10x + y
husband age = 10y + x
diff in ages = sum of ages/11
(10x + y) - (10y + x) = 1/11(10x + y + 10y + x)
9x - 9y = 1/11(11x + 11y)
9(x-y) = x+ y
9x - x = y + 9y
8x = 10y
x = 10y/8
put different values of y (y =1,2,3,4.........) to get
whole value of x

put y = 4, x = 5 satisfies the condition

woman age = 10(5) + 4
= 54
husband age = 45

Is This Answer Correct ?    4 Yes 1 No

I ASKED A WOMAN WHAT WAS HER AGE?. SHE REPLIED THAT HER HUSBAND'S AGE IS REVERSE OF HER. AND ..

Answer / take

IT WAS 45 FOR THE WOMAN, AND IT WAS 54 FOR HER HUSBAND.
54-45=9.
54+45=99.
(1/11)99=9.

SO THE ANSWER IS 45 AND 54.




woman age = 10x + y
husband age = 10y + x
diff in ages = sum of ages/11
(10x + y) - (10y + x) = 1/11(10x + y + 10y + x)
9x - 9y = 1/11(11x + 11y)
9(x-y) = x+ y
9x - x = y + 9y
8x = 10y
x = 10y/8
put different values of y (y =1,2,3,4.........) to get
whole value of x

put y = 4, x = 5 satisfies the condition

woman age = 10(5) + 4
= 54
husband age = 45

Is This Answer Correct ?    1 Yes 0 No

Post New Answer

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