Answer / vitthal kadam

#include<iostream.h>

int main ()
{
int num,cnt,temp;
char ch;
cout<< "Enter any number in between [0-99999]: ";
cin >> num;
temp = num;
cnt = 0;
while (temp)
{
if (temp%10 == 7)
cnt++;
temp = temp/10;
}
cout<<"count of 7 in the entered number is " << cnt ;
cin>>ch;
return 0;
}

Answer / ruchi

#include<stdio.h>
#include<conio.h>
int main()
{
int num,n,i=0,p;
printf("\nEnter the number ");
scanf("%d",&num);
while(num>0)
{
n=num%10;
p=num/10;
num=p;
if(n==7)
{
i++;
}
}
printf("\nthe total number of occurence of the digit 7
is %d",i);
getch();
}

Answer / kumar

#include <iostream>
#include <string>

using namespace std;

int main ()
{
string str;
cout << "Enter a 4 digit number with '7' in it:";
cin >> str;
str.resize(4);
cout << "The 4 digit numebr you have entered is:" << str
<<endl;
int ipos = 0, count =0;
ipos = str.find_first_of('7');
while (ipos!=-1)
{
count ++;
ipos = str.find_first_of('7',(ipos+1));
}
if (count)
cout <<"Number of '7' in the string: "<<count<<endl;
else
cout <<"There are no 7's in the string entered"<<endl;
return 0;
}

Answer / gundaraj

void main()
{
int a[4],i,count=0;
cout<<"enter 4 digit number";
for(i=0;i<=3;i++)
{
cin>>a[i];
if(a[i]==7)
count++;
}
cout<<"The number of 7's are "<<count;
}

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