Answer / prabhat

if(sizeof(no)==2)
cout<<"Integer";
else if(sizeof(no)==4)
cout<<"Float";

Answer / fakkad

incomplete solution.
why? what if no is "long int" or "double"?
in that case his solution will always print float.

Answer / rajat bera

bool __inline is_integer(float f){
int i = f;
return (f == static_cast<float>(i));
}


int main()
{
int num=0;
double num2= 1234;

num=num2;

if(is_integer(num2))

printf("the number is int");
else
printf("the number is float");

getch();


return 0;

}

Answer / vignesh1988i

one way according to me is to find through the no. of bytes allocated for that variable or the value itself directly...........


thank u

Answer / srv

Using sizeof() operator.


if(sizeof(no)==2)
cout<<"no is int";
else
cout<<"float";

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