Find greatest number out of 10 number without using loop.
- 5 Answers
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Answer / ashwin
#include<stdio.h>
int MAX(int a,int b)
{
if(a>b)
return a;
else
return b;
}
int max(int a[],int n)
{
if(n==1)
return a[0];
else
return MAX(a[n-1],max(a,n-1));
}
int main()
{
int a[]={3,5,1,5,7,3,9,0,2,6};
int n=10,big;
big=max(a,n);
printf("%d",big);
return 0;
}
| Is This Answer Correct ? | 8 Yes | 2 No |
Answer / dheeraj
#include<stdio.h>
#include<conio.h>
input(int a[]);
find(int []);
int i=0,a[10],j=0,max=0;
main()
{
clrscr();
printf("enter no");
input(a);
find(a);
printf("\nmax no is==%d",max);
}
input(int a[10])
{
i++;
scanf("%d",&a[i]);
if(i<10)
{
input(a);
}
}
find(int a[10])
{
if(j<10)
{
j++;
if(max<a[j])
{
max=a[j];
}
find(a);
}
}
| Is This Answer Correct ? | 9 Yes | 8 No |
Answer / khurshid alam
#include<stdio.h>
int show();
int main()
{
printf("The bigger value is:%d",show());
}
int show()
{
static int big=0,a=0,c=0;
printf("enter number");
scanf("%d",&a);
if(a>big)
big=a;
if(c<=10)
{
c++;
show();
}
return big;
}
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / satya
#include<stdio.h>
void main()
{
static int big=0,a=0,cnt=0;
printf("enter number");
scanf("%d",&a);
if(a>big)
big=a;
if(cnt<=10)
{
cnt++
main();
}
printf("largest number amongest 10 numbers is :%d",big);
}
| Is This Answer Correct ? | 4 Yes | 11 No |
Answer / joshi
/* for same qustion this */
void main()
{
int a,b;
clrscr();
printf (enter the two number :);
scanf("%d%d",a,b);
if (a>b)
printf ("%d\n greater number",a);
else
printf ("%d\n greter number",b);
getch();
}
| Is This Answer Correct ? | 11 Yes | 48 No |
Find the output? void main() {float a=2.0; printf("\nSize of a ::%d",sizeof(a)); printf("\nSize of 2.0 ::%d",sizeof(2.0));}
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