Answer / hassan noureddine

Use bit wise unary commands:

int i = 0x5678
char LowByte = (char) i; // yield 8;

To alter the bits

i &= 0xFF; // reset upper 2 bytes
i ^= 0xFFFF // invert all bits

Answer / vignesh1988i

we know that integer allocates 2 bytes of memory.
to get a single byte we must type cast the integer to character using pointers.

why because,when we take int i=10;,the binary representation for 10 is 1010 or in 8 bits it can be 0000 1010.
so in memory 2 bytes will be allocated as the whole for int.

let us consider: binary 10 address (2bytes)
0000 65534
0010 65535

in the memory according to the bytes prority the binary numbers will get stored.
so , our task is to take only one byte from int.

int i=10,*j;
j=&i;
printf('%d\n",(char*)j); // type casting of ptr varables

now. in the above ex. and according to the preceeded coding it will print 0 as the output ,which is the output from only one byte of memory location (65534).

any corrections , pl. notify me


thank u

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