Answer / suresh

Base class constructor called first next it wil call Derived
class constructor

Answer / sangeetha

"C++ classes honor their parents by calling their parents
constructor before they call their own." The base class
constructor will be called before the derived class
constructor. This makes sense because it guarantees that
the base class is properly constructed when the constructor
for the derived class is executed. This allows you to use
some of the data from the base class during construction of
the derived class.

Answer / prajeesh

#include <iostream>
using namespace std;

class BaseClass {
public:
BaseClass() { cout << "Constructing base portion\n"; }
~BaseClass() { cout << "Destructing base portion\n"; }
};

class DerivedClass: public BaseClass {
public:
DerivedClass() { cout << "Constructing derived
portion\n"; }
~DerivedClass() { cout << "Destructing derived
portion\n"; }
};

int main()
{
DerivedClass ob;

// do nothing but construct and destruct ob

return 0;
}
Constructing base portion
Constructing derived
Destructing derived
Destructing base portion

Answer / nathusingh

If both the base and derived class have constructors then
first of all constructor of the Base Class (Parent class)
will be invoked and then subsequently the constructor of
the derived class will be called.Whereas in case of
Destructors,destructor of the derived is called so as to
destroy the object child object and then base class
destructor is called. In Case of Creation ( constructors)
Parents(Base Class) are honored first while in case of
destruction (destrcutors) children( Derived class) are made
the victim :)

Answer / ctharam

1) First of all, Base class constructor called and then Derived class constructor will call.

Answer / harsha

First Constructor of base class will be invoked and then the
constructor of derived will be invoked ........

For example
Using System;
class Base
{
public Base()
{
Console.WriteLine("Base Class");
}
}
class Derived:Base
{
public Derived()
{
Console.WriteLine("Derived Class");
}
static void Main(string[] args)
{
Derived d=new Derived();
}
}

Output:
Base Class
Derived Class

Answer / nageswararao

Both Base and Derived class constructor Get invoked when
both base and derived has constructors and and we create an
object for derive class?

Answer / sachin moule

Base class constructor is get called first and later on
derived same will happen in case of destructor

Answer / amrit kumar singh

#include <iostream>
using namespace std;

class BaseClass {
public:
BaseClass() { cout << "Constructing base portion\n"; }
~BaseClass() { cout << "Destructing base portion\n"; }
};

class DerivedClass: public BaseClass {
public:
DerivedClass() { cout << "Constructing derived portion\n"; }
~DerivedClass() { cout << "Destructing derived portion\n"; }
};

int main()
{
DerivedClass ob;

// do nothing but construct and destruct ob

return 0;
}

output will be :-----------
Constructing base portion
Constructing derived
Destructing base portion
Destructing derived

Answer / dipa

It will show compilation error that "class type
redefination".

how can u change button shape at run time

3 Answers   Samsung,

what message is sent to an application when the user presses the primary button?

0 Answers   University Exams,

How we can findout Memoryleaks, In what way it can be avoided

6 Answers   Infosys,

What is socket?

3 Answers  

How to handle dynamic menus in MFC?

3 Answers   HCL,

Why not virtual functions to handle messages?

5 Answers  

Whats is DDX & DDV in MFC?

1 Answers   HCL,

I have 2 threads. One thread prints odd numbers and the second thread prints even numbers. Now, I have to execute the threads alternatively so that i can output 1,2,3,4,5,6,..... write code for this?

1 Answers  

How to update windows title bar dynamically?

7 Answers   HCL,

1)To Remove WS_MINIMIZEBOX in a Frame ?

1 Answers  

Tell us something about MFC?

7 Answers   Microsoft,

Hi All, I have created one MFC Dialog Based application.now if i am running the application its working fine,instead of closing he application i minimized the application,if i run the application again,i am getting the Dialog. I want to prevent the calling of application multiple times. please give me the code and let me know in which method i need to make changes. Praveer

7 Answers   HP,