if a five digit number is input through the keyboard, write
a program to calculate the sum of its digits.
(hint:-use the modulus operator.'%')
Answers were Sorted based on User's Feedback
Answer / synner
#include<stdio.h>
#include<math.h>
#include<conio.h>
void main()
{
long int num;
int sum=0,temp;
clrscr();
printf("Enter the numbe\n");
scanf("%ld",&num);
while(num!=0)
{
temp=num%10;
sum=sum+temp;
num=num/10;
}
printf("%d",sum);
getch();
}
Is This Answer Correct ? | 11 Yes | 20 No |
Answer / aha na
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,sum=0;
clrscr();
printf("\n enter a number",i);
scanf("%d",&i);
while(i<=0)
{
j=i%10;
sum=sum+j;
i=i/10;
}
printf("\n the sum of the digits
are:%d\n");
getch();
}
Is This Answer Correct ? | 14 Yes | 30 No |
Answer / jegadeesh
#include<stdio.h>
void main()
{
int i,j;
scanf("%d",&i);
if((i%9)==0)
printf("The sum of digit is 9");
else
{
j=i%9;
printf("%d",j);
}
}
//the above will print result as 6 if given as 12345 since
1+2+3+4+5=15 and proceeding 1+5 we get as 6.....
is this an apt answer...
Is This Answer Correct ? | 11 Yes | 36 No |
what is computer
print ur name 20,000 times without using inbuilt library functions like printf,scanf,gets,puts,getchar or putchar
18)struct base {int a,b; base(); int virtual function1(); } struct derv1:base{ int b,c,d; derv1() int virtual function1(); } struct derv2 : base {int a,e; } base::base() { a=2;b=3; } derv1::derv1(){ b=5; c=10;d=11;} base::function1() {return(100); } derv1::function1() { return(200); } main() base ba; derv1 d1,d2; printf("%d %d",d1.a,d1.b) o/p is a)a=2;b=3; b)a=3; b=2; c)a=5; b=10; d)none 19) for the above program answer the following q's main() base da; derv1 d1; derv2 d2; printf("%d %d %d",da.function1(),d1.function1(),d2.function1 ()); o/p is a)100,200,200; b)200,100,200; c)200,200,100; d)none 20)struct { int x; int y; }abc; you can not access x by the following 1)abc-->x; 2)abc[0]-->x; abc.x; (abc)-->x; a)1,2,3 b)2&3 c)1&2 d)1,3,4
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