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f1()
{
f(3);}
f(int t)
{
switch(t);
{
case 2: c=3;
case 3: c=4;
case 4: c=5;
case 5: c=6;
default: c=0;}
value of c?
- 5 Answers
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Answer / ningappa
The above code returns a compiler error:
1.In C functions cannot be made inline.
2.A semi-colon is not expected after switch.
| Is This Answer Correct ? | 7 Yes | 0 No |
Answer / madhu
As t = 3,it goes to case 3.But there is no break in that
case so it proceeds further down to default and c becomes 0.
| Is This Answer Correct ? | 7 Yes | 1 No |
Answer / poornima
Initially, switch statement is ended with semicolon.so
cases will not be alone without switch.It is compilation
error.
If semicolon is not there in switch statement answer is
zero.
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / shruti
Yeah value of c becomes 0 at the end of the program..
| Is This Answer Correct ? | 3 Yes | 1 No |
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