Answer / guest

Cause: An attempt was made to create a subtable(subview)
under a supertable(superview) located in another schema.

Action: Connect as schema owner of the superobject and retry
the operation.

Please add more information about this Error

DRG-10762: index owner does not have access to procedure string

1 Answers  

---

ORA-00358: Too many file members specified, the maximum is string

1 Answers  

---

PCC-02316: illegal operator in constant expression

1 Answers  

---

RMAN-05508: SET NEWNAME TO NEW not allowed (datafile string)

1 Answers  

---

PCC-02439: FOR clause not allowed in this COLLECTION statement

1 Answers  

---

---

ORA-28273: No mapping for user nickname to LDAP distinguished name exists.

2 Answers  

---

ORA-07586: spdcr: $SEARCH failure

1 Answers  

---

PLS-00139: duplicate external NAME specification in subprogram expression

1 Answers  

---

ORA-32775: cannot change size attributes of read only tablespace string

1 Answers  

---

ORA-25953: join index cannot be a functional index

1 Answers  

---

ORA-23455: flavor string contains object "string"

1 Answers  

---

ORA-19691: %s is from different database: id=string, name=string

1 Answers  

---