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How to write a program for swapping two strings without
using 3rd variable and without using string functions.
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Answer / sivaraj
Questions is to swap the string not for integers so the
above answers are wrong.
| Is This Answer Correct ? | 47 Yes | 7 No |
Answer / gaurav rustagi
#include <iostream>
#include <string.h>
using namespace std;
void swap ( char ** , char ** ) ;
int main ()
{
char * buyer= "US Dollars" ;
char * seller = "IN Ruppees" ;
cout << "Before swap, buyer has " << buyer;
cout << " and seller has " << seller << endl;
swap (buyer,seller);
cout << " After swap, buyer has " << buyer;
cout << " and seller has " << seller << endl;
return 0;
}
void swap ( char ** L , char ** R )
{
char ** temp = R;
R = L ;
L = temp ;
}
| Is This Answer Correct ? | 7 Yes | 13 No |
Answer / sri
main()
{
int a=5,b=3;
a=a+b;
b=a-b;
a=a-b;
printf(" %d %d ",a,b);
getch();
}
| Is This Answer Correct ? | 33 Yes | 42 No |
Answer / biswambar
main()
{
int a=5,b=3;
b=a+b;
a=b-a;
b=b-a;
printf(" %d %d ",a,b);
}
| Is This Answer Correct ? | 44 Yes | 54 No |
Answer / saptarshi
void main()
{
char *p="string1";
char *q="string2";
p^=q^=p^=q;
printf("%s,%s",p,q);
}
swapping the base pointers of the two strings may work...
if they are declared as character arrays, then it is not
possible as we cannot modify the value of array base
pointers...
| Is This Answer Correct ? | 10 Yes | 26 No |
Answer / ramu pasupuleti
#include<stdio.h>
#include<conio.h>
{
printf("enter a,b values");
a=a+b;
a=a-b;
b=a-b;
printf("%d%d",a,b);
getch();
}
| Is This Answer Correct ? | 2 Yes | 18 No |
Answer / srinath, hyd
main()
{
int a=5,b=3;
a=a+b;
b=a-b;
a=a-b;
printf(" %d %d ",a,b);
getch();
}
| Is This Answer Correct ? | 7 Yes | 26 No |
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