Can true be a variable name in c?
No Answer is Posted For this Question
Be the First to Post Answer
Write a program for the following series? 1 121 12321 1234321 123454321 12345654321 1234567654321 123456787654321 12345678987654321 1234567890987654321 123456789010987654321 12345678901210987654321 1234567890123210987654321 .........1234321............ ..........123454321............ ..........12345654321............ 7 8 9 0 1 Pls............?
What will be printed as the result of the operation below: #include<..> int x; int modifyvalue() { return(x+=10); } int changevalue(int x) { return(x+=1); } void main() { int x=10; x++; changevalue(x); x++; modifyvalue(); printf("First output:%d\n",x); x++; changevalue(x); printf("Second output:%d\n",x); modifyvalue(); printf("Third output:%d\n",x); }
Are comments included during the compilation stage and placed in the EXE file as well?
how do you programme Carrier Sense Multiple Access
which will return integer? a) int*s ( ) b) ( int* ) s( ) c) int ( *s ) ( )
How does memset() work in C?
plz answer.... write a program that reads line (using getline) e.g."345", converts each line to an integer using "atoi" and computes the average of all the numbers read. also compute the standard deviation.
What does double pointer mean in c?
how to print this pyramid * * * * * * * * * * * * *
How the C program can be compiled?
18)struct base {int a,b; base(); int virtual function1(); } struct derv1:base{ int b,c,d; derv1() int virtual function1(); } struct derv2 : base {int a,e; } base::base() { a=2;b=3; } derv1::derv1(){ b=5; c=10;d=11;} base::function1() {return(100); } derv1::function1() { return(200); } main() base ba; derv1 d1,d2; printf("%d %d",d1.a,d1.b) o/p is a)a=2;b=3; b)a=3; b=2; c)a=5; b=10; d)none 19) for the above program answer the following q's main() base da; derv1 d1; derv2 d2; printf("%d %d %d",da.function1(),d1.function1(),d2.function1 ()); o/p is a)100,200,200; b)200,100,200; c)200,200,100; d)none 20)struct { int x; int y; }abc; you can not access x by the following 1)abc-->x; 2)abc[0]-->x; abc.x; (abc)-->x; a)1,2,3 b)2&3 c)1&2 d)1,3,4
What tq means in chat?