Write a program for the following series? 1 121 12321 1234321 123454321 12345654321 1234567654321 123456787654321 12345678987654321 1234567890987654321 123456789010987654321 12345678901210987654321 1234567890123210987654321 .........1234321............ ..........123454321............ ..........12345654321............ 7 8 9 0 1 Pls............?

5 Answers  

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What will be printed as the result of the operation below: #include<..> int x; int modifyvalue() { return(x+=10); } int changevalue(int x) { return(x+=1); } void main() { int x=10; x++; changevalue(x); x++; modifyvalue(); printf("First output:%d\n",x); x++; changevalue(x); printf("Second output:%d\n",x); modifyvalue(); printf("Third output:%d\n",x); }

2 Answers  

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Are comments included during the compilation stage and placed in the EXE file as well?

0 Answers  

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how do you programme Carrier Sense Multiple Access

0 Answers  

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which will return integer? a) int*s ( ) b) ( int* ) s( ) c) int ( *s ) ( )

1 Answers   C DAC,

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How does memset() work in C?

2 Answers  

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plz answer.... write a program that reads line (using getline) e.g."345", converts each line to an integer using "atoi" and computes the average of all the numbers read. also compute the standard deviation.

1 Answers  

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What does double pointer mean in c?

0 Answers  

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how to print this pyramid * * * * * * * * * * * * *

2 Answers  

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How the C program can be compiled?

11 Answers   HP,

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18)struct base {int a,b; base(); int virtual function1(); } struct derv1:base{ int b,c,d; derv1() int virtual function1(); } struct derv2 : base {int a,e; } base::base() { a=2;b=3; } derv1::derv1(){ b=5; c=10;d=11;} base::function1() {return(100); } derv1::function1() { return(200); } main() base ba; derv1 d1,d2; printf("%d %d",d1.a,d1.b) o/p is a)a=2;b=3; b)a=3; b=2; c)a=5; b=10; d)none 19) for the above program answer the following q's main() base da; derv1 d1; derv2 d2; printf("%d %d %d",da.function1(),d1.function1(),d2.function1 ()); o/p is a)100,200,200; b)200,100,200; c)200,200,100; d)none 20)struct { int x; int y; }abc; you can not access x by the following 1)abc-->x; 2)abc[0]-->x; abc.x; (abc)-->x; a)1,2,3 b)2&3 c)1&2 d)1,3,4

1 Answers  

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What tq means in chat?

0 Answers  

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