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Hi, I am new in oracle(SQL), could anyone help me in writing a correct SQL. Below is the table structure. Table: Subsc Fields: 1. Sub_no (this field will hold values of subscriber nos, for e.g. S111111, S222222, S333333, S444444, etc.) 2. s_status (this field will hold values for different status of subscriber, for e.g. 'A', 'S', 'C', etc.) 3. cus_id (this field will hold values of bill nos for e.g. 11111111, 22222222, 33333333, 44444444, etc.) Table: Bill Fields: 1. Bill_no this field will hold values of bill nos for e.g. 11111111, 22222222, 33333333, 44444444, etc.) 2. b_status = (this field will hold values for different status of bill for e.g. 'O', 'C', 'S', etc.) Note: 1. The Sub_no is a Primary key of Subsc table. 2. The cus_id is a foreign in Subsc table (referred from Bill_no field of Bill table) 3. The Bill_no field is the Primary key of Bill table. Query A --> I wrote a query to select cus_id/Bill_no which is in status open (b_status = 'O') and having more than two active subscriber (i.e. S_status = 'A') in it ( i.e. more the two subscribers in same bill). select s.cus_id from subsc s where exists (select 1 from bill where bill_no = s.cus_id and b_status = 'O') and s_status = 'A' group by s.cus_id having count(sub_no) = 2 Problem : The above query will give the cus_id (or rather bill_no) which are in open status (b_status ='O) and which are having TWO ACTIVE Subscribers (s_status ='A') in it. However, this query will also lists the cus_id/bill_no which are having more than TWO subscribers in it (but only two subscriber will be in Active status (s_status = 'A') and the others will be in s_status = 'C' or s_status = 'S'. Help needed: I want to write a query which will fetch ONLY the cus_id/bill_no which are in open status (b_status ='O') and which are having ONLY TWO ACTIVE subscribers (s_status ='A') in it. B--> If I include the sub_no in the above query then NO row are returned. select s.cus_id, s.sub_no from subsc s where exists (select 1 from bill where bill_no = s.cus_id and b_status = 'O') and s_status = 'A' group by s.cus_id, s.sub_no having count(sub_no) = 2 Help needed: I want to modify the above query which will fetch ONLY the cus_id/bill_no which are in open status (b_status ='O') and which are having ONLY TWO ACTIVE subscribers (s_status ='A') in it ALONG with the sub_no. Thanks a lot in advance. Regards, Nitin
create or replace procedure search_matter(empno varchar2) as sql_stmt varchar2(200); stmt varchar2(200); v_table_name varchar2(200); val_pres number; inp_value varchar2(200); type obj_typ is table of cols.column_name%type index by binary_integer; type all_col is table of varchar2(100) index by binary_integer; typ_obj_typ obj_typ; typ_all_col all_col; begin select object_name bulk collect into typ_obj_typ from user_tables,user_objects where table_name = object_name AND object_type = 'TABLE'; select empno into inp_value from dual; dbms_output.put_line('inp value : '||inp_value); for i in typ_obj_typ.first..typ_obj_typ.last loop v_table_name := NULL; v_table_name := typ_obj_typ(i); dbms_output.put_line(i||':'||typ_obj_typ(i)); dbms_output.put_line('....................'); sql_stmt := 'select column_name from cols where table_name = :1 and data_type in (''CHAR'', ''VARCHAR2'', ''NCHAR'', ''NVARCHAR2'',''NUMBER'')'; EXECUTE IMMEDIATE sql_stmt bulk collect into typ_all_col using typ_obj_typ(i); for inside in typ_all_col.first..typ_all_col.last loop dbms_output.put_line('sql stmt: '||sql_stmt); dbms_output.put_line('column name: '||typ_all_col(inside)||'table name: '||typ_obj_typ(i)); stmt := 'select count(*) from ||typ_obj_typ(i)||'; EXECUTE_IMMEDIATE stmt into val_pres ; if val_pres = 1 then dbms_output.put_line('value present col name: '||typ_all_col(inside)||'table name :'||typ_obj_typ(i)); end if; end loop; dbms_output.put_line('....................'); end loop; exception when others then dbms_output.put_line('sql code '||sqlcode||'Table name: '||v_table_name); dbms_output.put_line('sql message '||sqlerrm); end; Compile-time I am getting below error, Plz help to resolve. LINE/COL ERROR -------- ----------------------------------------------------------------- 47/23 PLS-00103: Encountered the symbol "STMT" when expecting one of the following: := . ( @ % ;
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