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Table 1: col1 Timestamp ---------------- 01-mar-2012 11:12:46 Table 2: col2 Timestamp -------------------- 01-mar-2012 11:12:10 01-mar-2012 11:11:23 Write a query to display a row with table2 col2 value less than tabl1 col1 value. Maximum timestamp value previous to table1 col1 value. Display a result as: Col1 col2 ----- ----- 01-mar-2012 11:12:46 01-mar-2012 11:12:10
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how to check the 3rd max salary from an employee table? One of the queries used is as follows: select sal from emp a where 3=(select count(distinct(sal)) from emp b where a.sal<=b.sal). Here in the sub query "select count(distinct(sal)) from emp b where a.sal<=b.sal" or "select count(distinct(sal)) from emp b where a.sal=b.sal" should reveal the same number of rows is in't it? Can any one here please explain me how is this query working perfectly. However, there is another query to get the 3rd highest of salaries of employees that logic I can understand. Pls find the query below. "select min(salary) from emp where salary in(select distinct top 3 salary from emp order by salary desc)" Please explain me how "select sal from emp a where 3=(select count(distinct(sal)) from emp b where a.sal<=b.sal)" works source:http://www.allinterview.com/showanswers/33264.html. Thanks in advance Regards, Karthik.
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