Answer / rajesh

Both are Equal length: L
Thick's burning rate: L/6
Thin's burning rate: L/4
After X hours (at bed time) of burning, remaining lengths:
Thick: L-(LX/6) and Thin: L-(LX/4)
But, at X hours, thick is twice as long as thin. i.e.:
L-(LX/6)=2[L-(LX/4)]
1-(X/6)=2-(X/2)
Solve for X and get 3.

Answer / tarun

the thicker candle lights for 6 hrs , so in 1 hr it will
reduce in length by L/6

similarly the thinner candle will reduce in length by L/4.

applying trial and check

eg. after 3 hrs
reduced length of thicker candle = L/6 *3 = 0.5 L
there fore length remaining of thicker candle = L- 0.5 L
= 0.25 L
similarly reduced length of thinner candle after 3 hrs
= L/4 * 3 = 0.75 L
there fore length remaining of thinner candle = L-0.75 L
= 0.25 L

as can be seen length remaining of thicker candle is twice
the length remaining of thinner candle.

Answer / shashi

Hay the eassiest way to understand the answer is :
just assume that the length of the candel is 12 cm
now the burning rate is as follow's
now the thinner will last upto 4 hours so the rate of
burning will be 3cm/hr and for the thicker it will be 2cm/hr
Hours Thinner Thicker
First hour 3cm 2cm
second hr 6cm 4cm
third hr 9cm 6cm

so after three hr's the length of the remaining candel is
for THINNER it is 3 cm
for THICKER it is 6 cm
now the thicker is twice the length of thinner

Answer / jothi

Thick length = 1 - t/6
Thin length = 1 - t/4
At time T, (1 - T/6) = 2*(1-T/4)
This gives T = 3.

Answer / gourav mahipal

Candles were ligthen till they last. CoZ there is no
description that the candles were unlight them. How can u
say that ramesh lit the candles for 2 or 4 hours.

Answer / prasanta guha

ramesh lit the candle for two hours.
description:
thicker can lit for 6 hrs
thinner can lit for 4 hrs
if both lit for two hours then 6-2 =4 and 4-2= 2 will be
left that will be twice of the length

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