How to print all the arguments provided to the script?
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Hi, all Scripting professional. Q. I have written script1.sh and calling script2.sh in script1.sh file using bash shell as interpreter and my log in shell also bash shell.My code like Script1 #!/bin/bash echo "My script2 call" . script2.sh Here script2.sh file run successfully but when I have changed my interpreter bash to ksh like #!/bin/ksh Error are comming script2.sh command not found. Guid me how to call other script in our main script.
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