I came across some code that puts a (void) cast before each call to printf. Why?
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while loop contains parts a) initialisation, evalution of an expression,increment /decrement b) initialisation, increment/decrement c) condition evalution d) none of the above
#‎include‬<stdio.h> void main() { int i; for(i=5;0;i++) { printf("%d",i); } }
simple c program for 12345 convert 54321 with out using string
N O S I E R + A S T R A L ---------------- 7 2 5 6 1 3
i = 25;switch (i) {case 25: printf("The value is 25 ");case 30: printf("The value is 30 "); When the above statements are executed the output will be : a) The value is 25 b) The value is 30 c) The value is 25 The value is 30 d) none
char ch=10;printf("%d",ch);what is the output
Write a program that takes a 5 digit number and calculates 2 power that number and prints it.
Program to swap the any two elements in an array containing N number of elements?
1 Answers Bosch, Glenwood, Ugam Solutions,
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