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Consider a language that does not have arrays but does have
stacks as a data type.and PUSH POP..are all defined .Show
how a one dimensional array can be implemented by using two
stacks.
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Answer / barun
In one stack keep values and in another stack keep index of
array. In other wards a[0] = 10. Then keep in bottom of
stack1 value 10 and in bottom of stack2 0. Both needs to be
synchronized in such implementation. Of course random access
is not possible.
| Is This Answer Correct ? | 6 Yes | 2 No |
Answer / gingercpu
One to pop and the other to push. Have to maintain all the
elements. Index converted to the # of push and pop
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / abdur rab
The arrays are always sequential, since we are going to use
stack, ther is no possibility for random access.
PUSH all the values in the stack1, then pop the value from
stack1 into stack2.
so whenever ther is a PUSH to stack1, we need to POP all
the elements from stack2 to stack1 and then PUSH the new
value. Now POP all the values from stack1 to stack2. It ud
work like a queue then.
| Is This Answer Correct ? | 4 Yes | 3 No |
How would you rename a function in C?
You have an int array with n elements and a structure with three int members. ie struct No { unsigned int no1; unsigned int no2; unsigned int no3; }; Point1.Lets say 1 byte in the array element is represented like this - 1st 3 bits from LSB is one number, next 2 bits are 2nd no and last 3 bits are 3rd no. Now write a function, struct No* ExtractNos(unsigned int *, int count) which extracts each byte from array and converts LSByte in the order mentioned in point1.and save it the structure no1, no2, no3. in the function struct No* ExtractNos(unsigned int *, int count), first parameter points to the base address of array and second parameter says the no of elements in the array. For example: if your array LSB is Hex F7 then result no1 = 7, no2 = 2, no3 = 7. In the same way convert all the elements from the array and save the result in array of structure.
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