what is importance of data sturture in a programming language?

22 Answers   L&T, TCS, Wipro,

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What is the default width for ouputting a long integer using the insertion operator?

0 Answers  

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Badboy is defined who has ALL the following properties: 1. Does not have a girlfriend and is not married. 2. He is not more than 23 years old. 3. The middle name should be "Singh" 4. The last name should have more than 4 characters. 5. The character 'a' should appear in the last name at least two times. 6. The name of one of his brothers should be "Ram" Write a method: boolean isBadBoy(boolean hasGirlFriend , boolean isMarried, int age , String middleName , String lastName , String[] brotherName); isHaveGirlFriend is true if the person has a girlfriend isMarried is true if the person is married age is the age of the person middleName is the middle name of the person lastName is the last name of the person brotherName is the array of the names of his brothers

1 Answers  

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How many keywords are used in c++?

0 Answers  

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If you don’t declare a return value, what type of return value is assumed?

0 Answers  

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Discuss the possibilities related to the termination of a program before entering the mainq method?

0 Answers  

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what are the iterator and generic algorithms.

0 Answers  

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What is size of a object of following class? class Foo { public: void foo(){} }

2 Answers   CA,

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Can we get the value of ios format flags?

0 Answers  

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When volatile can be used?

3 Answers   Symphony,

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Do the names of parameters have to agree in the prototype, definition, and call to the function?

0 Answers  

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how can i access a direct (absolute, not the offset) memory address? here is what i tried: wrote a program that ask's for an address from the user, creates a FAR pointer to that adress and shows it. then the user can increment/decrement the value in that address by pressing p(inc+) and m(dec-). NOW, i compiled that program and opened it twice (in 2 different windows) and gave twice the same address to it. now look what happen - if i change the value in one "window" of the program, it DOES NOT change in the other! even if they point to the same address in the memory! here is the code snippet: //------------------------------------------------------ #include <stdio.h> //INCLUDE EVERY KNOWN HEADER FILE #include <conio.h> //FOR ANY CASE... #include <iostream.h> #include <dos.h> #include <process.h> main() { int far *ptr; //FAR POINTER!!! long address; char key=0; //A KEY FROM THE KEYBOARD int temp=0; clrscr(); cout<<"Enter Address:"; cin>>hex>>address; //GETS THE ADDRESS clrscr(); (long)ptr=address; temp=*ptr; //PUTS THE ADDRESS IN THE PTR cout<<"["<<hex<<(unsigned long)ptr<<"]="<<*ptr<<" = "<< (char)(*ptr); //SHOWS: [address]=value=ASCII symbol. while (key!=27) //WHILE YOU DONT PRESS ESC. { while(!kbhit()) //WHILE KEY IS NOT PRESSED { if (temp!=*ptr) { temp=*ptr; clrscr(); cout<<"["<<hex<< (unsigned long)ptr<<"]="<<*ptr<<" = "<<(char)(*ptr); }; //IF THE VALUE HAS CHANGED, CLEAR THE SCREEN AND SHOW //AGAIN if (key=='p') {key=0; (*ptr)++; } //INCREMENT VALUE if (key=='m') {key=0; (*ptr)--; } //DEC. VALUE }; key=getch(); //IF A KEY IS PRESSED, READ IT FROM THE //KEYBOARD }; return 0; //IF ESC WAS THE KEY, EXIT THE PROGRAM } //---------------------------------------------------------

0 Answers  

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