Answer / nimish singh

A conversion constructor declared with the explicit keyword. The compiler does not use an explicit constructor to implement an implied conversion of types. It's purpose is reserved explicitly for construction.

What is an orthogonal base class in c++?

0 Answers  

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class X { public: int x; static void f(int z); }; void X::f(int y) {x=y;} What is the error in the sample code above? a) The class X does not have any protected members. b) The static member function f() accesses the non-static z. c) The static member function f() accesses the non-static x. d) The member function f() must return a value. e) The class X does not have any private members.

2 Answers   Quark,

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How to write a program such that it will delete itself after exectution?

3 Answers  

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Can a class be static in c++?

0 Answers  

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How can I improve my c++ skills?

0 Answers  

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how to swap two numbers with out using temp variable

12 Answers   Global eProcure, TCS,

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Can non-public members of another instance of the class be retrieved by the method of the same class?

0 Answers  

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Which c++ compiler is best?

0 Answers  

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Explain stack & heap objects?

0 Answers  

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What are the advantages of C++ programming compared to C programming?

2 Answers   HAL,

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What is stoi in c++?

0 Answers  

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write the prime no program in c++?

16 Answers  

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