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The gene for tallness (T) is dominant over the gene for
shortness (t) in pea plants. A homozygous dominant pea
plant is crossed with a heterozygous pea plant, and 200
seeds are produced. Approximately how many of these seeds
can be expected to produce plants that are homozygous
dominant?
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when a homozygous tall (TT) is crossed with heterozygous
tall (Tt) they will segregate in ratio of 1:1. Thus there
would be nearly 100 seeds of each type. thus the no. of
seeds for homozygous dominant would be 100.
Homozygous Tall (TT) x Heterozygous Tall (Tt)
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TT, Tt
(1 : 1)
| Is This Answer Correct ? | 9 Yes | 0 No |
Answer / mounika
1 out of 4 will be homozygous dominant as per law..so 50 out
of 200 will be homozygous dominent
| Is This Answer Correct ? | 15 Yes | 7 No |
Answer / viswa
150 out of 200 seeds are to be homozygous dominant
(TT)....according to mendle laws of cross over......
| Is This Answer Correct ? | 1 Yes | 10 No |
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