main() {int i=5; // line 1 i=(++i)/(i++); // line 2 printf("%d",i); // line 3 } output is 2 but if we replace line 2 and line 3 by printf("%d",i=(++i)/(i++)); then output is 1. Why?

1 Answers   GATE,

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difference between semaphores and mutex?

1 Answers  

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How do I declare an array of N pointers to functions returning pointers to functions returning pointers to characters?

2 Answers  

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Who developed c language?

0 Answers  

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How do you write a program which produces its own source code as its output?

4 Answers  

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void main() { int s[4][2]={ {1234,56},{1212,33},{1434,80},{1312,78} }; int (*p)[2]; int i,j,*pint; for(i=0;i<=3;i++) { p=&s[i]; pint=p; printf("\n"); for(j=0;j<=1;j++) printf("%d",*(pint+j)); } } while running this program it shows a warning-suspicious pointer conversion ie pint=p; my que is why should we assign the value of p to pint again.why cant we use it directly as *(p+j)..but if i use like tat the o/p is garbage value..

1 Answers  

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Differentiate between #include<...> and #include '...'

0 Answers  

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how to devloped c lenguege?

4 Answers  

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program for following output using for loop? 1 2 2 3 3 3 4 4 4 4 5 5 5 5 5

8 Answers   Aptech, Infosys,

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Explain what is the benefit of using const for declaring constants?

0 Answers  

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What are the functions to open and close file in c language?

0 Answers  

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How many levels of indirection in pointers can you have in a single declaration?

0 Answers   Agilent, ZS Associates,

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