what is the value of b
if a=5;
b=++a + ++a
Answers were Sorted based on User's Feedback
Answer / sagar
here in b=++a + ++a;
a
Initial Value 5
First Prefix 6
Second Prefix 7
Final Equation b = 7 + 7 = 14...
So,correct answer is 14....
if the equation was as below:
c=++a;//a==6
d=++a;//a=7
b=c+d;//b=6+7=13
then b==13...
Is This Answer Correct ? | 97 Yes | 29 No |
Answer / madhu cherukuri
a=5
b=++a +++a;
ANS:14
in this case the data will be storing in CPU register so the
result is 14 only.
volatile int a=5;
b=++a + ++a;
ANS:13
the data will be stored in directly memory
Is This Answer Correct ? | 33 Yes | 15 No |
Answer / naresh
Not a very tough question. Important thing to note that in
any expression pre increment operator has a higher prority
than arithemetic operator as a result value of a is
increment is first two times then value of b is evaluated.
So b = 7*7 = 14.
in first ++a we get a=6
in next ++a we get a=7
and b=7+7=14
This question will result in same output for most of the
compilers, but some rare compiler may produce an entire
diffrenent parse tree resulting in an undefined result
Is This Answer Correct ? | 28 Yes | 13 No |
Answer / anup dixit
13 is the correct answers. I'm attaching here a small java
program which proves this:
The program is:
------------------------------------------------------------
public class TestAddition
{
public static void main(String[] args)
{
int a=5;
System.out.println("1..Before a was : "+a);
int b = ++a + ++a;
System.out.println("Final a was : "+a+ ", int b =
++a + ++a is: "+b);
a=5;
System.out.println("2..Before a was : "+a);
int c= ++a+(++a);
System.out.println("Final a was : "+a+", int c=
++a+(++a) is: "+c);
}
}
------------------------------------------------------------
The output is:
------------------------------------------------------------
1..Before a was : 5
Final a was : 7, int b = ++a + ++a is: 13
2..Before a was : 5
Final a was : 7, int c= ++a+(++a) is: 13
Is This Answer Correct ? | 15 Yes | 10 No |
Answer / kaps
IT is defenetly 14...Ans = 14
Explanation:
Because ++a = 6
then again ++a = 7
Now compiler replace the both value with 7 (because of both
are of value of a).
So 7+7 = 14.
It is tested on turbo C...
try with adding one more ++a will give u ans 24(8+8+8) for
++a + ++a + ++a.
Is This Answer Correct ? | 8 Yes | 3 No |
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