Interested to Buy Any Domain ? << Click Here >> for more details...
when asub class inherits a super class and overrides a
public method of super class in sub class(public method in
super class).
why these methods needs to be public in sub class.
(otherwise compile time error).
- 3 Answers
- 6685 Views
- I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / imtiyaz
The access specifier for the overriding method can allow
more but not less access than the overridden method.
For example, a protected method in the superclass can be
made public but not private
private, protected and public is Ascending order of access
modifiers depending upon the strength
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / ravikiran
the access specifies sould not me more restrictive in a
subclass.
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / sushila
if super class method is public, then override method should
be public.
override method will take same access specifier or expanded one.
the order of access specifier is
private > default > protected > public
| Is This Answer Correct ? | 1 Yes | 0 No |
why do we use interface in java?
What is a file pointer?
What are the approaches that you will follow for making a program very efficient?
Which is better arraylist or vector?
What are dot operator queries?
What is design pattern and there types?
Explain an algorithm to find depth of a binary tree.
0 Answers Akamai Technologies,
How does synchronized modifier work?
Explain the scope of a variable.
What do you mean by JVM?
How do singleton patterns work?
What is javac in java?
Core Java 
