Answer / prasad jvv

Disks are block devices. Mean one block of data can be read
at one point of time. So there is no point of time between
read one byte and another byte. If intended to calculate
time to read one byte, first of all we need to calculate
the time required to read one block and devide that by
block size.

Access Time = Command Overhead Time + Seek Time + Settle
Time + Latency

This equation is not universal standard.

Answer / daniele

http://www.linuxinsight.com/how_fast_is_your_disk.html


% sudo hdparm -t /dev/hda

/dev/hda:
Timing buffered disk reads: 140 MB in 3.02 seconds = 46.28
MB/sec

Substitute /dev/hda with the name of your raw disk device,
of course (for example, it might be /dev/sda if you're using
libata, or something else).

Answer / arbit

I suppose the answer is to be figured out programmatically
not by handwaving. Every stupid in Computer Science knows
what you have answered

write an interactive C program that will encode or decode a line of text.To encode a line of text,proceed as follows. 1.convert each character,including blank spaces,to its ASCII equivalent. 2.Generate a positive random integer.add this integer to the ASCII equivalent of each character.The same random integer will be used for the entire line of text. 3.Suppose that N1 represents the lowest permissible value in the ASCII code,and N2 represents the highest permissible value.If the number obtained in step 2 above(i.e.,the original ASCII equivalent plus the random integer)exceeds N2,then subtract the largest possible multiple of N2 from this number,and add the remainder to N1.Hence the encoded number will always fall between N1 and N2,and will therefore always represent some ASCII character. 4.Dislay the characters that correspond to the encoded ASCII values.  The procedure is reversed when decoding a line of text.Be certain,however,that the same random number is used in decodingas was used in encoding.

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