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Write a shell script to check whether a number is Armstrong number or not?
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Answer / kirtiranjan sahoo
read -p "Enter any number : " no
rev=0
temp=$no
while [ $no -ne 0 ]
do
dig=$(( $no%10 ))
rev=$(( $rev+$dig*$dig*$dig ))
no=$(( $no/10 ))
done
if [ $rev -eq $temp ]
then
echo "Armstrong"
else
echo "Not Armstrong"
fi
| Is This Answer Correct ? | 26 Yes | 23 No |
A file has multiple records each having three 30-bit long fields(field1,field2,field3).There is also a lookup file,LOOK_UP.dat.Now, we need to consider only the last ten digits of field1 and lookup the file LOOK_UP.dat. If there a match then field2 and field3 should replaced with corresponding data from the lookup file. otherwise that particular record,for which there is no match, should be stored in a seperate file.
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