How many bit combinations are there in a byte?
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Answer / abdullah javid
There'll actually be 256 combinations. The maximum value
that can be represented with a byte (8 - bits) is 255 but as
far as combinations are concerned 0 should also be
considered as well as 1, 2, 3, ..., 255. So there are total
256 combinations.
| Is This Answer Correct ? | 94 Yes | 8 No |
Answer / vaibhav meena
it is 2^8
means 2 ^ no of bits
means 256....
:)
| Is This Answer Correct ? | 28 Yes | 3 No |
Answer / azza
There are 256 combinations as 00000000 is classed a one
combination. plus the other 255 combinations. Answer 8 is
wrong.Answer 2 is correct.
| Is This Answer Correct ? | 19 Yes | 3 No |
Answer / santosh shah
256 combinations.Byte contains the 8 Bits and bit contains
either the value 0 or 1.i.e.(2 raise to power 8 minus
1).The maximum number of value represented with a byte is 8
bits is 255 but 0 should also be considered as well as 1,
2, 3, ..., 255. So there are total
256 combinations.
| Is This Answer Correct ? | 15 Yes | 6 No |
Answer / arjun
This has to be the easiest technical question for any
programmer...
A Byte is made of 8 Bits, so the number of combination for
Byte would be 2^8.
However, if asked the maximum number represented then it
would be (2^8)-1.
Surely, if you can't answer this you should seriously think
about changing your profession.
| Is This Answer Correct ? | 7 Yes | 4 No |
Answer / panaitsdv
if number of bite values is n, and length of the byte is k.
that means n = 2, k = 8.
for n even => n^k
(2^8 = 256)
for n odd => n^k - 1
(2^7 - 1 = 128-1 = 127)
| Is This Answer Correct ? | 5 Yes | 15 No |
Answer / k.kishorebabu
=2^8-1
=256-1
=255
bco'z only 8 bit data can be loaded that depends on the
address lines we take
| Is This Answer Correct ? | 1 Yes | 12 No |
this is to swap to strings....but in output the whole strings are swapped leaving first as it is...why it is so #include<iostream.h> int main() { char a[]="ajeet"; char b[]="singh"; long x=*a; long y=*b; cout<<x<<":"<<y; x=x+y; y=x-y; x=x-y; *a=x; *b=y; cout<<x<<":"<<y; cout<<&a<<endl; cout<<&b<<endl; }
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